Optimal. Leaf size=221 \[ -\frac{b^{3/2} (5 a B e-7 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}+\frac{b (5 a B e-7 A b e+2 b B d)}{\sqrt{d+e x} (b d-a e)^4}+\frac{5 a B e-7 A b e+2 b B d}{3 (d+e x)^{3/2} (b d-a e)^3}+\frac{5 a B e-7 A b e+2 b B d}{5 b (d+e x)^{5/2} (b d-a e)^2}-\frac{A b-a B}{b (a+b x) (d+e x)^{5/2} (b d-a e)} \]
[Out]
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Rubi [A] time = 0.52826, antiderivative size = 221, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182 \[ -\frac{b^{3/2} (5 a B e-7 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}}+\frac{b (5 a B e-7 A b e+2 b B d)}{\sqrt{d+e x} (b d-a e)^4}+\frac{5 a B e-7 A b e+2 b B d}{3 (d+e x)^{3/2} (b d-a e)^3}+\frac{5 a B e-7 A b e+2 b B d}{5 b (d+e x)^{5/2} (b d-a e)^2}-\frac{A b-a B}{b (a+b x) (d+e x)^{5/2} (b d-a e)} \]
Antiderivative was successfully verified.
[In] Int[(A + B*x)/((a + b*x)^2*(d + e*x)^(7/2)),x]
[Out]
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Rubi in Sympy [A] time = 53.8819, size = 207, normalized size = 0.94 \[ - \frac{b^{\frac{3}{2}} \left (7 A b e - 5 B a e - 2 B b d\right ) \operatorname{atan}{\left (\frac{\sqrt{b} \sqrt{d + e x}}{\sqrt{a e - b d}} \right )}}{\left (a e - b d\right )^{\frac{9}{2}}} - \frac{b \left (7 A b e - 5 B a e - 2 B b d\right )}{\sqrt{d + e x} \left (a e - b d\right )^{4}} + \frac{7 A b e - 5 B a e - 2 B b d}{3 \left (d + e x\right )^{\frac{3}{2}} \left (a e - b d\right )^{3}} - \frac{7 A b e - 5 B a e - 2 B b d}{5 b \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )^{2}} + \frac{A b - B a}{b \left (a + b x\right ) \left (d + e x\right )^{\frac{5}{2}} \left (a e - b d\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((B*x+A)/(b*x+a)**2/(e*x+d)**(7/2),x)
[Out]
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Mathematica [A] time = 0.758903, size = 191, normalized size = 0.86 \[ \frac{\sqrt{d+e x} \left (\frac{15 b^2 (a B-A b)}{a+b x}+\frac{30 b (2 a B e-3 A b e+b B d)}{d+e x}+\frac{10 (b d-a e) (a B e-2 A b e+b B d)}{(d+e x)^2}+\frac{6 (b d-a e)^2 (B d-A e)}{(d+e x)^3}\right )}{15 (b d-a e)^4}-\frac{b^{3/2} (5 a B e-7 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{(b d-a e)^{9/2}} \]
Antiderivative was successfully verified.
[In] Integrate[(A + B*x)/((a + b*x)^2*(d + e*x)^(7/2)),x]
[Out]
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Maple [B] time = 0.033, size = 403, normalized size = 1.8 \[ -{\frac{2\,Ae}{5\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}}+{\frac{2\,Bd}{5\, \left ( ae-bd \right ) ^{2}} \left ( ex+d \right ) ^{-{\frac{5}{2}}}}+{\frac{4\,Abe}{3\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-{\frac{2\,Bae}{3\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-{\frac{2\,Bbd}{3\, \left ( ae-bd \right ) ^{3}} \left ( ex+d \right ) ^{-{\frac{3}{2}}}}-6\,{\frac{A{b}^{2}e}{ \left ( ae-bd \right ) ^{4}\sqrt{ex+d}}}+4\,{\frac{Babe}{ \left ( ae-bd \right ) ^{4}\sqrt{ex+d}}}+2\,{\frac{{b}^{2}Bd}{ \left ( ae-bd \right ) ^{4}\sqrt{ex+d}}}-{\frac{A{b}^{3}e}{ \left ( ae-bd \right ) ^{4} \left ( bxe+ae \right ) }\sqrt{ex+d}}+{\frac{Ba{b}^{2}e}{ \left ( ae-bd \right ) ^{4} \left ( bxe+ae \right ) }\sqrt{ex+d}}-7\,{\frac{A{b}^{3}e}{ \left ( ae-bd \right ) ^{4}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+5\,{\frac{Ba{b}^{2}e}{ \left ( ae-bd \right ) ^{4}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+2\,{\frac{B{b}^{3}d}{ \left ( ae-bd \right ) ^{4}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((B*x+A)/(b*x+a)^2/(e*x+d)^(7/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^2*(e*x + d)^(7/2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.235421, size = 1, normalized size = 0. \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^2*(e*x + d)^(7/2)),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x+A)/(b*x+a)**2/(e*x+d)**(7/2),x)
[Out]
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GIAC/XCAS [A] time = 0.236931, size = 587, normalized size = 2.66 \[ \frac{{\left (2 \, B b^{3} d + 5 \, B a b^{2} e - 7 \, A b^{3} e\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )} \sqrt{-b^{2} d + a b e}} + \frac{\sqrt{x e + d} B a b^{2} e - \sqrt{x e + d} A b^{3} e}{{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )}{\left ({\left (x e + d\right )} b - b d + a e\right )}} + \frac{2 \,{\left (15 \,{\left (x e + d\right )}^{2} B b^{2} d + 5 \,{\left (x e + d\right )} B b^{2} d^{2} + 3 \, B b^{2} d^{3} + 30 \,{\left (x e + d\right )}^{2} B a b e - 45 \,{\left (x e + d\right )}^{2} A b^{2} e - 10 \,{\left (x e + d\right )} A b^{2} d e - 6 \, B a b d^{2} e - 3 \, A b^{2} d^{2} e - 5 \,{\left (x e + d\right )} B a^{2} e^{2} + 10 \,{\left (x e + d\right )} A a b e^{2} + 3 \, B a^{2} d e^{2} + 6 \, A a b d e^{2} - 3 \, A a^{2} e^{3}\right )}}{15 \,{\left (b^{4} d^{4} - 4 \, a b^{3} d^{3} e + 6 \, a^{2} b^{2} d^{2} e^{2} - 4 \, a^{3} b d e^{3} + a^{4} e^{4}\right )}{\left (x e + d\right )}^{\frac{5}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x + A)/((b*x + a)^2*(e*x + d)^(7/2)),x, algorithm="giac")
[Out]